Answer:
Please find the progeny of this cross below:
AaBb (1/4)
Aabb (1/4)
aaBb (1/4)
aabb (1/4)
Explanation:
According to this question, a fruit fly of genotype AaBb is crossed to another fruit fly of genotype aabb. This cross is a typical dihybrid cross involving two genes A and B. The following gametes will be produced by parents of this cross:
AaBb- AB, Ab, aB, ab
aabb- ab, ab, ab, ab
Using these gametes in a punnet square (see attached image), 16 offsprings or progeny in following proportion will be produced:
- AaBb (1/4)
- Aabb (1/4)
- aaBb (1/4)
- aabb (1/4)
