Answer:
Explanation:
To know how fast will she be moving after dropping 10m in elevation, we will use the equation of motion
v² = u²+2gS
S is the elevation
g is the acceleration due to gravity
v is the final velocity
u is the initial velocity
Substitute the given values
v² = 4²+2(9.81)(10)
v² = 16+(19.62)(10)
v² = 16+196.2
v² = 212.2
v = √212.2
v = 14.57m/s
Hence she will be moving at 14.57m/s
