Answer:
The specific rotation of the compound is +84.6°.
Explanation:
The specific rotation of the compound can be found using the following equation:
[tex] [\alpha] = \frac{\alpha}{c*l} [/tex]
Where:
α: is the observed rotation of a solution = +11°
c: is the concentration
l: is the pathlength = 10 cm = 1.0 dm
[tex] [\alpha] = \frac{\alpha}{c*l} = \frac{+11}{\frac{1.3 g}{10 mL}*1.0 dm} = +84.6 ^{\circ} [/tex]
Therefore, the specific rotation of the compound is +84.6°
I hope it helps you!
