Answer:
0.12 C.
Explanation:
The following data were obtained from the question:
Capacitor (C) = 10 mF
Potential difference (V) = 12 V
Charge (Q) =?
Next, we shall convert 10 mF to farad (F). This can be obtained as follow:
1 mF = 1×10¯³ F
Therefore,
10 mF = 10 mF × 1×10¯³ F/ 1mF
10 mF = 0.01 F
Therefore, 10 mF is equivalent to 0.01 F.
Finally, we shall determine the charge on the capacitor as illustrated below:
Capacitor (C) = 0.01 F
Potential difference (V) = 12 V
Charge (Q) =?
Q = CV
Q = 0.01 × 12
Q = 0.12 C
Therefore, the charge on the capacitor is 0.12 C.
