A 1000-turn toroidal solenoid has a central radius of 4.2 cm and is carrying a current of 1.7 A. What is the magnitude of the magnetic field inside the solenoid at the central radius

Respuesta :

Answer:

The value is  [tex]B  =  0.008095 \ T [/tex]

Explanation:

From the question we are told that

  The  number of turn is N  =  1000 turns

   The radius is  [tex]r =  4.2 \  cm =  0.042 \  m[/tex]

   The current is  [tex]I  =  1.7 \  A[/tex]

Generally the magnetic field is mathematically represented as

      [tex]B  =  \frac{\mu_o  *  N *  I  }{2 \pi r }[/tex]

Here [tex]\mu _o[/tex] is the permeability of free space with value

        [tex]\mu _o =   4\pi * 10^{-7} N/A^2[/tex]

So  

    [tex]B  =  \frac{4\pi * 10^{-7}  *  1000 *  1.7 }{2* 3.142 * 0.042 }[/tex]

=>  [tex]B  =  0.008095 \ T [/tex]