Answer:
[tex]k_2=1.379x10^{-2}s^{-1}[/tex]
Explanation:
Hello.
In this case, for a normal reaction, when we know the rate constant at a determined temperature, we can compute at another temperature via the Arrhenius equation specified for temperature change:
[tex]k_2=k_1exp[-\frac{Ea}{R}(\frac{1}{T_2}-\frac{1}{T_1} )][/tex]
In such a way, the rate constant at 9.50x10² K is:
[tex]k_2=3.241x10^{-5}s^{-1}exp[-\frac{255000}{8.314}(\frac{1}{950}-\frac{1}{800} )]\\\\k_2=1.379x10^{-2}s^{-1}[/tex]
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