Answer:
The first three terms of the sequence are 19, 25 and 31.
Step-by-step explanation:
Let [tex]f(x) = 6\cdot x +13[/tex], which defines a sequence for [tex]x \geq 1[/tex]. This is a case of an arithmetic progression. We obtain the first three terms of the sequence by evaluating the given function at [tex]x = 1[/tex], [tex]x = 2[/tex] and [tex]x = 3[/tex], respectively. That is:
x = 1
[tex]f(1) = 6\cdot (1)+13[/tex]
[tex]f(1) = 19[/tex]
x = 2
[tex]f(2) = 6\cdot (2) +13[/tex]
[tex]f(2) = 25[/tex]
x = 3
[tex]f(3) = 6\cdot (3) +13[/tex]
[tex]f(3) = 31[/tex]
The first three terms of the sequence are 19, 25 and 31.
