Light travels slower in oil than in air. If a light wave moves through the oil at a speed of 2 x 108 m/s and the wavelength of this light wave is 2 x 10-3 m, what is the frequency of this wave?

1 x 105 Hz
4 x 10-24 Hz
4 x 105 Hz
1 x 1011 Hz

Respuesta :

The frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct. Frequency is the inverse of the time period.

What is the frequency?

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

The given data in the problem is;

v is the speed of light =  2 x 10⁸ m/s

[tex]\lambda[/tex] is the wavelength = 2 x 10⁻³ m,

f is the frequency of the wave is to be found;

Frequency is given by the formula as,

[tex]\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{2 \times 10^8}{2 \times 10^-3} \\\\ \rm f = 1 \times 10^{11} \ Hz[/tex]

Hence the frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct.

To learn more about the frequency reference  the link;

https://brainly.com/question/14926605