Quantity of dry fish food with Fred :-
[tex] = 6 \frac{3}{4} \: pounds[/tex]
Number of containers he will divide it into = 5
Quantity of food in each container :-
[tex] = 6\frac{3}{4} \div 5[/tex]
[tex] = \frac{(4 \times 6 + 3)}{4} \div 5[/tex]
[tex] = \frac{(24 + 3)}{4} \div \frac{5}{1} [/tex]
[tex] = \frac{27}{4} \div \frac{5}{1} [/tex]
[tex] = \frac{27}{4} \div \frac{1}{5} [/tex]
[tex] = \frac{27 \times 1}{4 \times 5} [/tex]
[tex] = \frac{27}{20} [/tex]
[tex] = 1 \frac{7}{20} [/tex]
Therefore , each container contains :-
[tex]1 \frac{7}{20} \: pounds \: of \:d ry \: fish \: food \: .[/tex]
