Write an equation for the parabola that has a vertex of (-1,8) and goes through the point of (2,-10)

Answer:
Standard Form:
[tex]y=2x^{2} -4x+6[/tex]
Vertex Form:
[tex]y=-2(x+1)^{2} +8[/tex]
Step-by-step explanation:
General equation:
[tex]y=a(x-h)^{2}+k[/tex]
To find a, substitute the points to the general equation.
vertex (h,k)
(2, -10) (x,y)
Find y, use the general equation and substitute the vertex points (h,k) and a to get the standard form.