Answer:
29.21%
Explanation:
first of all we have to find the mass percentage of Cr in Cr2O3
molar mass of Cr2O3,
Molar Mass = 2 x Molar Mass(Cr) + 3 x Molar Mass(O)
= 2x52.0 + 3x16.0
= 104+48
= 152 g/mol
the Molar Mass of Cr2O3 = 152
we will calculate the mass of this element
mass of Cr = 2xMolarMass of (Cr)
= 104 g
Mass percentage of Cr = (104x100)/152
= 10400/152
= 68.42 %
therefore,
the fraction of Cr in ore is the fraction of Cr in Cr2O3 multi[plied by fraction of Cr2O3 in ore
42.7%
= 0.427
= 0.6842 * 0.427
= 0.292
1
when converted to %
= 29.21%
Answer: 29.21 %
