In quadrilateral ABCD shown below it is known that BC is perpendicular CD, angle A=5x+12, and angle C=7x-36. Given this information, which of the following is the degree measure of angle A?

Answer:
m∠A = 102°
Step-by-step explanation:
In quadrilateral ABCD, BC is perpendicular to CD
m∠BCD = 90°
(7x - 36) = 90°
7x = 90 + 36
7x = 126
x = 18
Since, m∠A = (5x + 12)
Therefore, m∠A = (5×18) + 12
= 90 + 12
= 102°
Measure of angle A = 102°