Step-by-step explanation:
Hey there!
The given equation is; y= -3/4x+1...........(i)
The equation of a line which passes through point (9,12) is;
(y-y1) = m2(x-x1)
(y-12) = m2(x-9).................(ii)
From equation (i)
y = -3/4x+1
Slope (m1) = -3/4
As per the condition of perpendicular lines;
m1*m2= -1
[tex] - \frac{3}{4} \times m2 = - 1[/tex]
-3m2 = -4
[tex]m2 = \frac{ - 4}{ - 3} [/tex]
Therefore, m2= 4/3.
Putting value of m2 in eqaution (i).
(y-12) = 4/3(x-9)
[tex]y - 12 = \frac{4}{3} x - 9 \times \frac{4}{3} [/tex]
[tex]y = \frac{4}{3} x - 3 + 12[/tex]
Therefore, the equation is; y = 4/3x +9.
Hope it helps...
