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The Space Shuttle is initially traveling at a constant speed of 2.0 x 10^3 m/s. It then accelerates at 50 m/s^2 for a distance of 1.0 x 10^4 m. What is its new speed after traveling this distance?

Respuesta :

jeremiahkevinm

Answer:

v^2 = u^2 + 2as

Given that,

u^2 =2.0 x 10^3 m/s.

a =50 m/s^2

s = 1.0 x 10^4 m

[tex]v = \sqrt{ {u}^{2} + 2as } \\v = \sqrt{ {(2 \times {10}^{3} )}^{2} + 2 \times 50 \times {10}^{4} } \\ v = 2236.06 \: m {s}^{ - 1} [/tex]

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