Number 17 thanks pls ASAP ASAP

Answer:
[tex]\frac{1}{2}[/tex] which agrees with answer B
Step-by-step explanation:
First write the equation that represents this type of variation:
[tex]y=\frac{5}{x}[/tex]
then we need to solve for "x" when y = 10 as shown below:
[tex]y=\frac{5}{x} \\10=\frac{5}{x} \\10*x=5\\x=\frac{5}{10} \\x=\frac{1}{2}[/tex]