Answer:
[tex]\huge\boxed{y=-\dfrac{1}{4}x+2}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
[tex]m[/tex] - slope
[tex]b[/tex] - y-intercept (0, b)
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
[tex](x_1;\ y_1);\ (x_2;\ y_)[/tex] - points on the line
From the graph we have two points (look at the picture)
[tex](4;\ 1)[/tex] and [tex](0; 2)\to b=2[/tex]
Calculate the slope:
[tex]m=\dfrac{2-1}{0-4}=\dfrac{1}{-4}=-\dfrac{1}{4}[/tex]
Put the values of [tex]m[/tex] and [tex]b[/tex] to the equation of a line:
[tex]y=-\dfrac{1}{4}x+2[tex]
