Answer:
4.083g
Step-by-step explanation:
12 g of a radioactive substance are present initially and eight years later only 6 g remain, how much of the substance will be present after 11 years
Starting with half life, we want to find k.
In a 4 year period, t=8 and A quantity will be reduced to (1/2)*A.
(1/2)= e^k8
In(1/2)