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A pitched ball is hit by a batter at a 45° angle and just clears the outfield fence, 107 m away. If the fence is at the same height as the pitch, find the velocity of the ball when it left the bat. Ignore air resistance.

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Answer:

31 m/s

Explanation:

[tex]R=\frac{v^2i sin(20)}{g}[/tex]

[tex]98=\frac{v^2i sin(2)*(45))}{9.80}[/tex]

[tex]98=\frac{v^2i sin (90)}{9.80}[/tex]

[tex]98=\frac{v^2i}{9.80}[/tex]

[tex]ui=31 m/s[/tex]

Answer:

31 m/s

Explanation:

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