The required value of f(x) when x = 0.5 is 16.
Given,
f(x) varies directly with x .
f(x)=160 when x = 5.
We have to find f(x) when x = 0.5
According to the question ;
A function f(x) that varies directly with x. Direct variation is a case of variation expresses as the following form:
f(x) = kx
The value k is a nonzero constant greater than zero and is called the constant of variation.
This indicates that f(x) increases as x increases.
So,
f( x ) = kx
[tex]k = \frac{f (x) }{x}\\\\ k = \frac{f(5)}{5}[/tex]
[tex]k = \frac{160}{5}[/tex]
k = 32
When x = 0.5,
Then , f(x) = 32x
f(x) = 32(0.5)
f(x) = 16
The required value of f(x) when x = 0.5 is 16.
For more information about the System of equations click the link given below .
brainly.com/question/13799715
