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James's Dog, Buddy, is 2 years older than Fluffy, the neighbor's cat. Three Years ago, Buddy was three times older than fluffy. How old are the dog and cat now?

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Answer: The cat is 4 years old, and the dog is 6 years old.

Step-by-step explanation:

We know that Buddy is 2 years old than Fluffy.

And 3 years ago, Buddy was 3 times older than Fluffy.

Let's define the variables:

B = age of Buddy

F = age of Fluffy.

The first statement can be written as:

B = F + 2

The second statement can be written as:

B - 3 = 3*(F - 3)

To solve this, we can replace the first equation into the second one, and solve that for F

B - 3 = 3*(F - 3)

(F + 2) - 3 = 3*F - 9

F - 1 = 3*F - 9

-1 + 9 = 3*F - F

8 = 2*F

8/2 = 4 = F

Fluffy is 4 years old, and with the first equation we can find the age of Buddy.

B = F + 2 = 4 + 2 = 6

Buddy is 6 years old

The required age of the dog buddy is 6 years old and the age of cat fluffy is 4 years old.

Given ,

James's dog buddy is 2 years older than Fluffy,

And the neighbor's cat Three Years ago, Buddy was three times older than fluffy.

Let ,

The age of buddy = B

The age of fluffy is = F

According to the question ,

Buddy, is 2 years older than Fluffy= Age of Buddy = Age of fluffy + 2 years older.

B = F +2

Again According to the question,

Three years ago age of Buddy = B - 3

Three years ago age of Fluffy = F - 3

Three years ago Buddy was three times older than fluffy = Three years ago age of Buddy = 3 × Three years ago Age of fluffy

B - 3 = 3 ( F - 3 )

Solving the equations,

B - 3 = 3 ( F - 3 )

Put the value of B from equation 1

F + 2 - 3 = 3 ( F -3 )

F - 1 = 3F - 9

F - 3F = - 9 +1

-2F = -8

2F = 8

[tex]F = \frac{8}{2}[/tex]

F = 4

The age of fluffy is 4 years old.

Then ,

The age of buddy

B = F + 2

B = 4 + 2

B = 6

The age of buddy is 6 years old.

The required age of the dog buddy is 6 years old and the age of cat fluffy is 4 years old.

For more information about system of equation click the link given below.

https://brainly.in/question/27545639

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