Answer:
Explanation:
The new pressure can be found by using the formula for Boyle's law which is
[tex]P_1V_1 = P_2V_2[/tex]
Since we are finding the new pressure
[tex]P_2 = \frac{P_1V_1}{V_2} \\[/tex]
From the question we have
[tex]P_2 = \frac{11.2 \times 0.86}{15} = \frac{9.632}{15} \\ = 0.64213333...[/tex]
We have the final answer as
Hope this helps you
Given:
Initial Volume [tex] \sf (V_1) [/tex] = 11.2 L
Initial Pressure [tex] \sf (P_1) [/tex] = 0.860 atm
Final Volume [tex] \sf (V_2) [/tex] = 15.0 L
To Find:
Final Pressure [tex] \sf (P_2) [/tex]
Concept/Theory:
[tex] \bf{ \underline{Boyle's \: Law} \: (Pressure - Volume \: Relationship)}[/tex]
"At constant temperature, the pressure of a fixed amount of gas varies inversely with the volume of the gas."
[tex] \bf{P \propto \dfrac{1}{V} \: (at \: constant \: T \: and \: n)}[/tex]
It can be also stated as "At constant temperature, the product of pressure and volume of fixed amount of a gas remains constant."
[tex] \bf{PV = Constant}[/tex]
If the initial pressure and volume of a fixed amount of gas at constant temperature are [tex] \sf (P_1) [/tex] & [tex] \sf (V_1) [/tex] and final pressure of the gas is [tex] \sf (P_2) [/tex] and volume occupied is [tex] \sf (V_2) [/tex], then according to Boyle's law;
[tex] \bf{P_1V_1 = P_2V_2 = Constant}[/tex]
OR
[tex] \bf{\dfrac{P_1}{P_2} = \dfrac{V_2}{V_1}}[/tex]
Answer:
By using Boyle's Law, we get:
[tex] \rm \longrightarrow \dfrac{0.860}{P_2} = \dfrac{15.0}{11.2} \\ \\ \rm \longrightarrow P_2 = \dfrac{11.2}{15.0} \times 0.860 \\ \\ \rm \longrightarrow P_2 = \dfrac{9.632}{15.0} \\ \\ \rm \longrightarrow P_2 = 0.642 \: atm[/tex]
[tex] \therefore [/tex] Final Pressure [tex] \sf (P_2) [/tex] = 0.642 atm
