To determine how many solutions this system has, we must solve the system first. We start by using substitution to solve for x.
[tex]y = 3x + 2\\y - 2x = 4\\\\3x + 2 - 2x = 4\\\\x + 2 = 4\\\\x = 2[/tex]
Now we plug in what we found x back into one of the original equations to solve for y.
[tex]y = 3(2) + 2\\\\y = 6 + 2\\\\y = 8[/tex]
With this information we can now answer the question.
We can conclude that this system has C. exactly 1 solution, [tex](2, 8)[/tex].
The number of solutions does the system of equations is to be considered as the option c. Exactly 1 solution.
Since
y = 3x + 2
And, y - 2x = 4
So, we can write
3x + 2 -2x = 4
x + 2 = 4
x = 2
Now
y = 3(2) + 2
= 6 + 2
= 8
hence, The number of solutions does the system of equations is to be considered as the option c. Exactly 1 solution.
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