The temperature of the xenon : 180.863 K
Combined with Boyle's law and Gay Lussac's law
[tex]\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}[/tex]
P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = final gas pressure
V2 = finalgas volume
T1 = initial gas temperature (K)
T2 = final gas temperature
P1=251 kPa
T1=-18+273=255 K
V1=1.9 L
P2=205 kPa
V2=1.65 L
[tex]\tt \dfrac{251\times 1.9}{255}=\dfrac{205\times 1.65}{T_2}\\\\T_2=\dfrac{205\times 1.65\times 255}{251\times 1.9}=180.863~K[/tex]
