please show your work for the question belowe

Answer:
Step-by-step explanation:
1. covert the displacement to meter.
1 in = 0.0254 m
so 60 in ×0.0254 m /1 in =1.524 m
2.calculate the initial and final velocity
Vi= 0
Vf=(1.524-0)/3= 0.508[m/s]
3.find the acceleration
a= (0.508-0)/3=
[tex]0.169m \div {s }^{2} [/tex]