An object is accelerating at -6.2 m/s? It comes to a stop after 2.0 seconds. What was its initial velocity?
A. -2.7 m/s
B. 2.7 m/s
C. 12.4 m/s
D. -12.4 m/s
NEED ASAP.
WILL GIVE BRAINLIEST.

Respuesta :

Answer:

C. 12.4 m/s

Explanation:

Acceleration (a) = -6.2 m/s²

Final velocity (v) = 0 m/s (Comes to rest)

Time taken (t) = 2.0 s

By using equation of motion, we get:

[tex] \bf \longrightarrow v = u + at \\ \\ \rm \longrightarrow 0 = u + ( - 6.2)(2.0) \\ \\ \rm \longrightarrow 0 = u - 12.4 \\ \\ \rm \longrightarrow u - 12.4 = 0 \\ \\ \rm \longrightarrow u + 12.4 - 12.4 = 0 + 12.4 \\ \\ \rm \longrightarrow u = 12.4 \: m {s}^{ - 1} [/tex]

[tex] \therefore [/tex] Initial velocity (u) = 12.4 m/s