fatima833
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Moving truck makes the displacement of (180m) toward east in period of(9.0s). What is the average velocity of the truck?someone please help!!

Respuesta :

quasarJose

Answer:

20m/s due east

Explanation:

Given parameters:

Displacement  = 180m due east

Time taken = 9s

Unknown:

Average velocity of the truck  = ?

Solution:

The average velocity is the displacement divided by the time taken;

   Average velocity  = [tex]\frac{displacement}{time}[/tex]  

Insert the parameters and solve;

 Average velocity = [tex]\frac{180}{9}[/tex]   = 20m/s due east

[tex]\mathrm {Hey, there!}[/tex]

Let's solve your problem:

20 m/s due east is your answer.

For this question, we will use the displacement method.

The displacement method states:

You divide the larger number by the smaller number.

--- [tex]\mathrm {Equation}[/tex] - [tex]\mathrm {180m / 9.0 = 20.0}[/tex]

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