the perimeter of a rectangle pool is 74 feet. if the length is one more than twice the width, find the dimensions of the pool

Respuesta :

Step-by-step explanation:

let length of the pool be l feet and width be w feet.

l = 2w + 1 --(1)

2(l + w) = 74 --(2)

sub (1) into (2):

2(2w + 1 + w) = 74

6w = 72

w = 12

therefore, length is 25feet and width is 12feet

Topic: Simultaneous eqn

If you like to venture further, do check out my insta (learntionary) where I regularly post useful math tips! Thank you!