Answer:
Step-by-step explanation:
The nth term of an AP is expressed as;
Tn = a+(n-1)d
a is the first term
n is the number of terms
d is the common difference
Sixth term
T6 = a+(6-1)d
T6 = a+5d
Third term;
T3 = a+(3-1)d
T3 = a+2d
If the sixth term of an AP is twice the 3rd term, then
a+5d = 2(a+2d)
a+5d = 2a+4d
Given a = 3
3+5d = 2(3)+4d
5d-4d = 6-3
d = 3
Common difference is 3
For the 10th term
T10 = a+9d
T10 = 3+9(3)
T10 = 3+27
T10 = 30
Hence the tenth term is 30
