Complete question is;
A long steel beam has a length of twenty-five meters on a coldday when the temperature is 0°C. What is the length of the beam on a hot day when T = 40°C. (α_steel = 1.1 × 10^(-5) °/C)
a. 25.00044 m
b. 25.0044 m
c. 25.011 m
d. 25.044m
e. 25.11 m
Answer:
Option C: 25.011 m
Step-by-step explanation:
We are given;
Initial Temperature; T1 = 0°C
Final Temperature; T2 = 40°C
Coefficient of linear expansion of steel; α_steel = 1.1 × 10^(-5) °/C
Initial length; L_o = 25 m
We know that formula for change in length is;
ΔL = LαΔT
Plugging in the relevant values, we have;
ΔL = 25 × 1.1 × 10^(-5) × (40 - 0)
ΔL = 0.011 m
Thus, new length is;
L1 = L_o + ΔL
L1 = 25 + 0.011
L1 = 25.011
