Answer:
350 g BaSO₄
General Formulas and Concepts:
Chemistry - Stoichiometry
Explanation:
Step 1: Define
1.5 mol BaSO₄
Step 2: Identify Conversions
Molar Mass of Ba - 137.33 g/mol
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of BaSO₄ - 137.33 + 32.07 + 4(16.00) = 233.4 g/mol
Step 3: Convert
[tex]1.5 \ mol \ BaSO_4(\frac{233.4 \ g \ BaSO_4}{1 \ mol \ BaSO_4} )[/tex] = 350.1 g BaSO₄
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
350.1 g BaSO₄ ≈ 350 g BaSO₄