Answer:
48.5%
Step-by-step explanation:
Given parameters:
Distance after first half = 50.5yd
Distance at the end of game = 75yd
Unknown:
Percent increase in the number of yards he carried = ?
Solution:
To find the percent increase;
Percent increase = [tex]\frac{change in distance}{distance at half time}[/tex] x 100
Percent increase = [tex]\frac{75 - 50.5}{50.5}[/tex] x 100 = 48.5%