Answer:
=29
Step-by-step explanation:
2f(b)=28
divide by 2
f(b)=14
f(b)=3b-1
3b-1=14
add 1 on both sides
3b=15
divide by 3
b=5
f(5)=14
let's plug that in
f(2×5)=3(2×5)-1
f(10)=30-1
f(10)=29
The value of f(2b) is 29 if f(x) = 3x - 1 and 2f(b) = 28 the answer is 29.
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have:
f(x) = 3x - 1 and 2f(b) = 28
Plug x = b
f(b) = 3b - 1
2f(b) =2(3b - 1)
2f(b) = 28
28 = 2(3b - 1)
b = 5
f(2b) = f(2(5)) = f(10)
f(10) = 3(10) - 1
f(10) = 30 - 1 = 29
Thus, the value of f(2b) is 29 if f(x) = 3x - 1 and 2f(b) = 28 the answer is 29.
Learn more about the function here:
brainly.com/question/5245372
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