Respuesta :
Answer:
v = 0.119 m/s
Explanation:
Given that,
Force constant, k = 3200 N/m
Mass, m = 65 kg
Amplitude of her oscillation is 1.7 cm i.e. 0.017 m
We need to find her maximum speed during the measurement. Let it is v. It is given by the formula as follows :
[tex]v=\sqrt{\dfrac{k}{m}}A[/tex]
Where,
A is the amplitude
[tex]v=\sqrt{\dfrac{3200}{65}}\times 0.017 \\\\v=0.119\ m/s[/tex]
So, the maximum speed is 0.119 m/s.
The maximum speed of the astronaut during the measurement is 0.12 m/s.
The given parameters;
- force constant, k = 3200 N/m
- mass of the astronaut, m = 65 kg
- amplitude of the oscillation, A = 1.7 cm = 0.017 m
The maximum speed of the astronaut during the measurement is calculated as follows;
[tex]v = \omega A\\\\v = \sqrt{\frac{k}{m} } \times A\\\\v = \sqrt{\frac{3200}{65} } \times 0.017\\\\v = 0.12 \ m/s[/tex]
Thus, the maximum speed of the astronaut during the measurement is 0.12 m/s.
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