contestada

a pot of water at 20.0ºC is warmed to 100º when 40000cal is added. what is the mass of the water?

Respuesta :

Answer:

500 g

Explanation:

m = Mass of water

c = Specific heat of water = [tex]1\ \text{cal/g}^{\circ}\text{C}[/tex]

[tex]\Delta T[/tex] = Temperature difference = [tex]100-20=80^{\circ}\text{C}[/tex]

Q = Heat added = 40000 cal

Heat is given by

[tex]Q=mc\Delta T\\\Rightarrow m=\dfrac{Q}{c\Delta T}\\\Rightarrow m=\dfrac{40000}{1\times 80}\\\Rightarrow m=500\ \text{g}[/tex]

The mass of water is 500 g.