assume all vars are positive reals

Answer:
[tex]\frac{x^{3}\sqrt[3]{x} }{4}[/tex]
Step-by-step explanation:
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What this is saying is it is taking the cubed root (which is like a square root, except it is using a 3 instead of 2) of x to the power of 10 divided by 64.
The equation is also saying:
[tex]\frac{\sqrt[3]{x^{10} }}{\sqrt[3]{64} }[/tex]
We can simplify the bottom half of the fraction to be 4. The cube root of something is essentially saying its the number times itself 3 times (in this case, divided by that original number). The number to get to 64 was 4 and it was done like this: 4 times 4 times 4 (which equals 64).
As for the top equation, it will simplify down to [tex]x^{3} \sqrt[3]{x}[/tex].
Since [tex]x^{10}[/tex] can be broken up to be x and [tex]x^{9}[/tex], we cube root the [tex]x^{9}[/tex] to become [tex]x^{3}[/tex], while the x remains the same.
We come to result of [tex]\frac{x^{3}\sqrt[3]{x} }{4}[/tex], which is the answer.
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