Respuesta :

Answer:

Required Answer:-

  • If [tex]\triangle[/tex] ABC is a isosceles triangle then
  • AB=BC

Now Substitute values

[tex]\longrightarrow[/tex][tex]\sf 3x-4=5x-10[/tex]

[tex]\longrightarrow[/tex][tex]\sf 5x-10=3x-4 [/tex]

[tex]\longrightarrow[/tex][tex]\sf 5x-3x=-4+10 [/tex]

[tex]\longrightarrow[/tex][tex]\sf 2x=6 [/tex]

[tex]\longrightarrow[/tex][tex]\sf x={\dfrac {6}{2}}[/tex]

[tex]\longrightarrow[/tex][tex]\sf x=3 [/tex]

[tex]\therefore[/tex][tex]\sf AB=3x-4=3\times 3-4=9-4 \\ \sf AB=5units [/tex]

Step-by-step explanation:

Side AB and Side BC are the same so we can make them equal to each other:

3x -4 = 5x -10

Subtract 3x from both sides.

-4 = 2x -10

Add 10 to both sides.

6 = 2x

Divide both sides by 2

3 = x

x = 3

Now substitute x in the expression

3x -4

3(3) -4

PEMDAS

9 - 4

Subtract

5