Answer:
44.8g
Explanation:
The reaction equation is given as:
4Fe + 3O₂ → 2Fe₂O₃
Given:
Mass of O₂ = 19.2g
Unknown:
Amount of iron used =?
Solution:
To solve this problem, we adopt the mole concept.
Since we know the mass of O₂;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of O₂ = 2(16) = 32g/mol
Number of moles = [tex]\frac{19.2}{32}[/tex] = 0.6moles
From the balanced reaction equation;
4 moles of Fe will react with 3 moles of O₂
0.6moles of O₂ will react with [tex]\frac{0.6 x 4}{3}[/tex] = 0.8mole of Fe
Mass of Fe = number of moles x molar mass
= 0.8 x 56
= 44.8g
