Answer:
19.0476 kN/m^2
Explanation:
Given data:
Dimension of rectangular area = 2.5m x 5.0m
external load = 150 KN/m^2
load depth = 6.25 m
calculate the vertical stress increase due to load at depth 6.25
we will use the approximate method which is
[tex]V_{s} = \frac{qBL}{(B +Z)(L+Z)}[/tex] ------- (1)
q = 150 kN/m^2
B = 2.5 m
L = 5 m
Z = 6.25 m
substitute the given values into the equation (1) above
hence the Vs ( vertical stress ) = 19.0476 kN/m^2
