Answer:
[tex]\theta=4.5^{\circ}[/tex]
Explanation:
Given that,
The distance between reflecting planes is 0.541 nm, d = 0.541 nm
Let the wavelength is 0.085 nm
We need to find the smallest angle, measured from these planes, at which constructive interference. Using Bragg's equation to find it as follows :
[tex]m\lambda=2d\sin\theta[/tex]
For smallest angle, m = 1
[tex]\theta=\sin^{-1}(\dfrac{m\lambda}{2d})\\\\\theta=\sin^{-1}(\dfrac{1\times 0.085\ nm }{2\times 0.541\ nm })\\\\\theta=4.5^{\circ}[/tex]
So, the smallest angle is 4.5 degrees.
