When [tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex] is divided by x - 1, the only true conclusion is g(1) = 0
The given equation is:
[tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex]
x- 1 is a factor of [tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex] only if g(1) = 0
Let us find g(1) by substituting x = 1 into [tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex]
[tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex]
[tex]g(1) = 1^4+2(1^3)-7(1^2)-8(1)+12\\\\g(1) = 1 + 2 - 7 - 8 + 12\\\\g(1) = -12 + 12\\\\g(1) = 0[/tex]
Therefore, when [tex]g(x) = x^4 + 2x^3-7x^2-8x+12[/tex] is divided by x - 1, the only true conclusion is g(1) = 0
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