(04.04 LC)
On a coordinate grid, point T is at (2,-4) and point Sis at (2,6). The distance (in units) between points T and Sis
numbers, such as 2.) (5 points)
(Input only whole

Respuesta :

Answer:

The distance 'd' between T and S:

  • [tex]d=10[/tex]

Step-by-step explanation:

As the point 'T' is located at (2, -4)

  • So, the point 'T' has the coordinates (2, -4)

And the point 'S' is located at (2, 6)

  • So, the point 'T' has the coordinates (2, 6)

The distance 'd' between T and S can be computed using the formula:

[tex]d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}[/tex]

[tex]=\sqrt{\left(2-2\right)^2+\left(6-\left(-4\right)\right)^2}[/tex]

[tex]=\sqrt{\left(2-2\right)^2+\left(6+4\right)^2}[/tex]

[tex]=\sqrt{0+10^2}[/tex]

[tex]=\sqrt{10^2}[/tex]

[tex]d=10[/tex]

Therefore, the distance 'd' between T and S:

  • [tex]d=10[/tex]

Answer:

t and s

Step-by-step explanation: