Answer:
The solution to the system of the equations will be:
[tex]x=3,\:y=1[/tex]
Step-by-step explanation:
Given the system of the equations
[tex]x+y=4[/tex]
[tex]x-y=2[/tex]
solving the system of the equations
[tex]\begin{bmatrix}x+y=4\\ x-y=2\end{bmatrix}[/tex]
[tex]x-y=2[/tex]
[tex]-[/tex]
[tex]\underline{x+y=4}[/tex]
[tex]-2y=-2[/tex]
solving
[tex]-2y=-2[/tex]
Divide both sides by -2
[tex]\frac{-2y}{-2}=\frac{-2}{-2}[/tex]
[tex]y=1[/tex]
[tex]\mathrm{For\:}x+y=4\mathrm{\:plug\:in\:}y=1[/tex]
[tex]x+1=4[/tex]
[tex]x=3[/tex]
Therefore, the solution to the system of the equations will be:
[tex]x=3,\:y=1[/tex]
