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A 0.12-m-radius grinding wheel takes 5.5 s to speed up from 2.0 rad/s to 11.0 rad/s. What is the wheel's average angular acceleration?

Respuesta :

abidemiokin

Answer:

0.56rad/s²

Explanation:

Using the equation of motion

wf = wi + αt

wf is the final angular velocity

wi is the initial angular velocity

α is the angular acceleration

t is the time

Given

wf = 11.0rad/s

wi =2.0rad/s

t = 5.5secs

Substitute into the formula and get α

11.0 = 2.0+5α

11.0-2.0 = 5α

9.0 = 5α

α = 5/9.0

α ≈ 0.56rad/s²

Hence the wheel's average angular acceleration is 0.56rad/s²

Lanuel

The wheel's average angular acceleration is equal to 1.64 [tex]rad/s^2[/tex].

Given the following data:

  • Radius = 0.12 meter
  • Time = 5.5 seconds
  • Initial angular velocity = 2.0 rad/s
  • Final angular velocity = 11.0 rad/s

To determine the wheel's average angular acceleration, we would apply the first equation of kinematics:

Mathematically, the angular acceleration of an object is given by the formula:

[tex]\alpha = \frac{\omega_f - \omega_i}{t}[/tex]

Where:

  • [tex]\omega_i[/tex] is the initial angular velocity.
  • [tex]\omega_f[/tex] is the final angular velocity.
  • t is the time.

Substituting the given parameters into the formula, we have;

[tex]\alpha =\frac{11.0\;-\;2.0}{5.5} \\\\\alpha =\frac{9.0}{5.5}[/tex]

Angular acceleration = 1.64 [tex]rad/s^2[/tex]

Read more: https://brainly.com/question/8898885

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