Answer:
10 g H₂SO₄
General Formulas and Concepts:
Chemistry - Stoichiometry
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
Step 1: Define
Given: 8 g SO₃
RxN: SO₃ + H₂O → H₂SO₄
Step 2: Identify Conversions
Molar Mass of S - 32.07 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H - 1.01 g/mol
Molar Mass of SO₃ - 32.07 + 3(16.00) = 80.07 g/mol
Molar mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol
Step 3: Stoichiometry
[tex]8 \ g \ SO_3(\frac{1 \ mol \ SO_3}{80.07 \ g \ SO_3} )(\frac{1 \ mol \ H_2SO_4}{1 \ mol \ SO_3} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} )[/tex] = 9.80042 g H₂SO₄
Step 4: Check
We are given 1 sig fig. Follow sig fig rules and round.
9.80042 g H₂SO₄ ≈ 10 g H₂SO₄
