Mass of AlCl₃ : 93.39 g
Further explanation
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
[tex]\large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So to find the number of moles can be expressed as
n = V x M
the volume of the solution = 330 cm³=0.33 dm³
the concentration of the solution = 283 g/dm³
mass of AlCl₃ :
[tex]\tt mass=V\times M\\\\mass=0.33\times 283=93.39~g[/tex]
