Answer:
the answer is 54 hope this helps lol
Step-by-step explanation:
Also this isnt high school level it's elementary RSM level.
The two-digit number in which the tens digit of the number is one more than the units digit is 54.
Algebraic expression are the expression which consist the variables, coefficients of variables and constants.
The algebraic expression are used represent the general problem in the mathematical way to solve them.
Let the unit digit be x. The tens digit of a two-digit number is one more than the units digit. Thus the unit digit is,
[tex]\rm \;tens\; digit=x+1[/tex]
Then the number is,
[tex]10(x+1)+x\\11x+10[/tex]
The reverse of this number is,
[tex]10x+x+1\\11x+1[/tex]
The difference between this number and the reverse number is 1/5 of the reverse number. Thus,
[tex]11x+10-(11x+1)=\dfrac{1}{5}(11x+1)\\9=\dfrac{1}{5}(11x+1)\\45=11x+1\\x=\dfrac{44}{11}\\x=4[/tex]
The unit digit is 4. Thus the tens digit is,
[tex](x+1)=4+1\\(x+1)=5[/tex]
Hence, the two-digit number in which the tens digit of the number is one more than the units digit is 54.
Learn more about the algebraic expression here;
https://brainly.com/question/2164351
