Complete the proof by providing the missing statement and reasons
Given: SD ⊥ HT; SH ≅ ST
Prove: ΔSHD = ΔSTD

Answer:
2. angle bisector splits into even halves
Step-by-step explanation:
that's all i can assist with sorry, proofs still confuse me!
Answer:
1. SD ⊥ HT 1. Given
2. ∠SDH and ∠SDT are right ∠s 2. Definition of perpendicular bisector
3. SH ≅ ST 3. Given
4. SD = SD 4. Reflexive Property
5. ΔSHD ≅ ΔSTD 5. HL Theorem