Answer:
total force = 4.704 × [tex]10^5[/tex] N
Explanation:
given data
height = 5 m
depth = 2 m
thick plastic = 8.00 m
depth = 4.00 m
solution
first we get here force in which aquarium fill with depth 2 m
dF = PdA ......1
F = ∫PdA
F = ∫ϼgy(wdy)
F = ϼgw ∫ y dy
F = ϼgw × [tex]\frac{y^2}{2}[/tex] .................2
F = [tex]1000 \times 9.8 \times 8 \times \frac{2^2}{2}[/tex]
F = 1.568 × [tex]10^5[/tex] N
and
now we get here force for depth 4 m
put here value in equation 2
F = [tex]1000 \times 9.8 \times 8 \times \frac{4^2}{2}[/tex]
F = 6.272 × [tex]10^5[/tex] N
so that here
total force will be
total force = 6.272 × [tex]10^5[/tex] N - 1.568 × [tex]10^5[/tex] N
total force = 4.704 × [tex]10^5[/tex] N
