How many total molecules will be present when the reaction of 5,000 molecules of CS2 with 15,000 molecules of 0 2 goes to completion?
CS2(1)+3 02(g) CO2(g) + 2S02(g)
(A) 5,000
(B) 10,000
(C) 15,000
(D) 20,000

Counting molecules, we see that the original 4 molecules in a 1:3 ratio become 1+2 = 3 molecules. The reactants present are in the necessary 1:3 ratio of CS₂ : O₂, so there are no limitations on the reaction. It can use all of the original molecules to produce ...

(3/4)(20,000) = 15,000

molecules of product.

When the reaction completes, there will be 15,000 molecules present.

How many total molecules will be present when the reaction of 5,000 molecules of CS2 with 15,000 molecules of 0 2 goes to completion? CS2(1)+3 02(g) CO2(g) + 2S02(g) (A) 5,000 (B) 10,000 (C) 15,000 (D) 20,000

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How many total molecules will be present when the reaction of 5,000 molecules of CS2 with 15,000 molecules of 0 2 goes to completion?
CS2(1)+3 02(g) CO2(g) + 2S02(g)
(A) 5,000
(B) 10,000
(C) 15,000
(D) 20,000