Answer:
The correct option is b: 1.0 s.
Explanation:
To find the time (t) at which the object reaches the ground we need to use the next equation:
[tex] y_{f} = y_{0} + v_{0}t - \frac{1}{2}gt^{2} [/tex] (1)
Where:
[tex]y_{f}[/tex]: is the final height = 0
[tex]y_{0}[/tex]: is the initial height = 5 m
[tex]v_{0}[/tex]: is the initial speed = 0 (it falls from rest)
g: is the gravity = 10 m/s²
By entering the above values into equation (1) we have:
[tex] 0 = 5m - \frac{1}{2}10 m/s^{2}t^{2} [/tex]
[tex]t = \sqrt{\frac{2*5 m}{10 m/s^{2}}} = 1 s[/tex]
Therefore, the correct option is b: 1.0 s.
I hope it helps you!
